Hi
I have a doubt in how pick order really works in 1vs1 match.
I thought that it was (fairly) 1A-2B-3B-4A with B getting first turn.
Then, this happened: https://www.warzone.com/MultiPlayer?GameID=22773638

So why D.Kan Ginger get is 3rd pick wich was my second ?
My conclusion is that even if both of us received first pick, the game randomly pick someone as being "A"player, so in this game it's me.
Is that right ?
If so isn't it a bit unfair for one player ?

A random player A is selected to go first out of A and B. They get their first pick. Then B gets their two lowest picks that are not occupied (if A's first pick is the same as B's, then 2 and 3, and if not, then 1 and 2. Then A gets their next two lowest picks that are not occupied. It follows the order ABBAABBAABB...

the game randomly picks an A player, they get #A1, then the B player gets his highest ranked spot that is still available #B1. if #B1 is not available he gets #B2, then because ita ABBA B gets #B2 or #B3 pick, then player A gets his #A2/3/4 pick

In that game, you got first pick, so Kan Ginger gets 1 and 3 since they were the lowest ranked picks not occupied by you.

Breaking it down to your linked game:
you get your smallest number - 1 (Africa)
he gets his smallest available pick - 1 (South America)
he gets his next available pick - 3 (Europe)
you get your next available pick - 4 (North America)

Next to this you already know that you got 2nd move in Turn 1 and that your opponent has your 2nd and 3rd pick

So everything as intended :)

btw - why did you surrender?

Edited 6/16/2020 10:12:42

The way Warzone distributes picks allows some interesting strategies:


In a 1v1 with 2 picks:

You can't lose both #1 and #2

You can't lose both #1 and #3

If you lose #1, you get #2 and #3, no matter what the opponent picked.

You can only get #4 if your opponent stole your #2 and #3 and you have second pick (you move first on the first turn.)

If you get your #4 you are guaranteed to get your #1, however the opposite is not necessarily true.



In a 1v1 with 3 picks:

You can't lose both #1 and #2

You can't lose both #1 and #3

If you lose #1, you get #2 and #3, no matter what the opponent picked.

You can't lose more than 1 pick if you have second pick, and if you have first pick, you can only lose more than one pick if you lose both #2 and #3, and that either means that your opponent picked them as their #1 and #2, or that you stole your opponent's #1 and you picked the same #2-3. In both cases you have first pick. (you go second in the first turn.)

You can only get #6 if your opponent stole both your #4 and #5 and you have second pick. (you move first on the first turn.)

If you get #6, it is very probable that you also got #3. The only way you can get #6 and not #3 is if the opponent picked your #3, #4, #5 as their #1, #2, #3.



If I posted anything incorrect, please tell me, I just want to help with what I know

Edited 6/17/2020 21:45:45