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Move Order: 10/4/2014 09:24:18


Master Ree 
Level 58
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I'm pretty sure the move order "rules" in a 2v2 game are if:

Team 1 - AB
Team 2 - CD

then if your teammate goes first, you go last [eg. A(CD)(DC)B or B(CD)(DC)A]. Correct me if I am wrong?

My real question is what if player C gets eliminated. Does the formula still hold?

If A then ADB, if B then BDA, if D then D(AB)?

Edited 10/4/2014 09:25:22
Move Order: 10/5/2014 12:07:34


Green 
Level 56
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I'd also be interested in the answer to this question. Does anyone know?
Move Order: 10/5/2014 13:32:58


timon92 
Level 62
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it goes like ADBBDAADBBDA... or BDAADBBDAADB... or DABBADDABBAD... or DBAABDDBAABD...

Edited 10/5/2014 13:41:32
Move Order: 10/6/2014 15:03:10


Master Ree 
Level 58
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Okay because I had a team game where I was the team with two (AB) and we eliminated the one opponent. The other guy then had 12 consecutive first moves against me (random order) and I wondered if he's just the luckiest person alive or something behind the scenes
Move Order: 10/6/2014 15:48:14


ChrisCMU 
Level 60
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I would think the slots hold the same (leave C in there as if not eliminated), then just no moves happen in that person's slot.
Move Order: 10/7/2014 21:18:01


Master Ree 
Level 58
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In that case then Team 1 could both have first move over the remaining player
Move Order: 10/7/2014 21:34:11


Beren • apex 
Level 63
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That still seems reasonable to me. Having a teammate get eliminated is (and should be) a significant handicap.
Move Order: 10/8/2014 13:19:32


ChrisCMU 
Level 60
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I'm not sure I am right, but I have always just considered that player to still be in the same position in the random order, just with no moves. It would be the same as if the player simply had no attacks/transfers at all, but was still in the game.
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